Question

Find the value of
${x}^{3} - 8 {y}^{3} - 36xy - 216 \: \: when \: x = 2y + 6$

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Answer 1

Answer:0

Step-by-step explanation:0

Answer 2

Answer:

$x {}^{3} - 8y {}^{2} - 36xy - 216 = 0 \\ at \: x = 0 \\ (2) {}^{3} - 8y {}^{2} - 36 \times 2 \times y - 216 = 0 \\ - 8y {}^{2} - 72y - 208 = 0 \\ y {}^{2} + 72y + 208 = 0 \\ find \: its \: roots \: that \: will \: the \: answer \: of \: this \: question$