Find the value of tg of a sequence, given
that tn=tn-1 + 2" and ti = 1.
Answers
Answered by
2
Step-by-step explanation:
n+2
=T
n
+
T
n+1
1
⇒T
n+2
−T
n
=
T
n+1
1
⇒T
n+2
⋅T
n+1
−T
n+1
⋅T
n
=1
Now, let a
n
=T
n+1
⋅T
n
⇒a
n+1
−a
n
=1
So, a
1
,a
2
,a
3
,...,a
n+1
form an A.P. with common difference, d=1; and first term a
1
=T
2
⋅T
1
=(1)(1)=1
Answered by
0
Answer:
bhag yaha se ok bakvas karta h
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