Question

Find the value of the 3 sin 10° -4 sin cube 10 degree​

Answer 1

$\: \: \: \: \:3 {sin10}^{o} - 4 {sin}^{3} {10}^{o} \\ \\ = sin {(3 \times 10)}^{o} \\ = sin {30}^{o} \\ = \frac{1}{2} \\ \\ \\ hence \\ 3sin {10}^{o} - 4 {sin}^{3} {10}^{o} = \frac{1}{2}$

Here, we used the identity

3sinA - 4sin³A = sin3A

Answer 2

Answer:

Formula we had -2sin a-4 sin a=sin2a

Step-by-step explanation:

sin 3a=sin 3(10)

=sin 30

=1/2

so

3sin 10- 4 sin cube 10=1/2

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