Find the value of the constant k that makes the function continuous
Answers
Answered by
0
Answer:
Given,
f(x)=
⎩
⎪
⎨
⎪
⎧
x
2
1−cos2kx
,
8,
when x
=0
when x=0
f(0)=8
If f(x) is continuous at x=0, then
x→0
lim
f(x)=f(0)
x→0
lim
x
2
1−cos2kx
=8
x→0
lim
k
2
x
2
2k
2
sin
2
kx
=8
⇒2k
2
x→0
lim
(
kx
sinkx
)
2
=8
⇒2k
2
×1=8
⇒k
2
=
2
8
⇒k=±2
Answered by
0
Answer:
Be Brainly!
MissCharm06 ❣️
Attachments:
Similar questions