Question

Find the value of the constant P for which 2p-1,5p+3,11 are the first three term of the AP

Answer 1

2p-1, 5p+3, 11

a2-a1 = a3-a2

5p+3-(2p-1) = 11-(5p+3)

5p+3-2p+1 = 11-5p-3

5p-2p+3+1 = 11-3-5p

3p+4 = 8-5p

3p+5p = 8-4

8p = 4

p = 4/8

p = 1/2 ans.