Question

find the value of the determinant |2 3 |
|1/2 -1/2|​

Answer 1

Answer:

-5/2

Step-by-step explanation:

|2 3|

|1/2 -1/2|

=2×-1/2 - 3×1/2

=-5/2

Answer 2

Value of the determinant is -5/2 for

$\left|\begin{array}{ccc} 2&3\\ \frac{1}{2} &-\frac{1}{2}\end{array}\right|$

Given:

• $\left|\begin{array}{ccc} 2&3\\ \frac{1}{2} &-\frac{1}{2}\end{array}\right|$

To Find:

• Value of The determinant

Solution:

For

$\left|\begin{array}{ccc} a&b\\ c &d\end{array}\right|$

Determinant is given by   ad - bc

Step 1:

Comparing

$\left|\begin{array}{ccc} 2&3\\ \frac{1}{2} &-\frac{1}{2}\end{array}\right|$  with $\left|\begin{array}{ccc} a&b\\ c &d\end{array}\right|$

a = 2 ,  b = 3  c = 1/2  , d = -1/2

Step 2:

Substitute values in ad - bc  and calculate the value

= 2(-1/2) - 3(1/2)

= - 1 - 3/2

= -5/2

Hence Value of the determinant is -5/2