Question

find the value of the discriminant
√5 x^2- x- √5 = 0
please answer correctly....solve step by step​

Answer 1

Answer:

√5x^2-x-5=ax^2-bx+c.

a=√5, b=-1,c=-5

discriminant = b^2-4ac

=(-1)^2-4(√5)(-5)

=1+20√5

Answer 2

Answer:

$\sqrt{5} {x}^{2} - x - \sqrt{5} = 0 \\ here \: \\ a = \sqrt{5} \: \: b = - 1 \: \: \: c = - \sqrt{5} \\ now \\ discriminant \: = {b}^{2} - 4 ac \\ = {( - 1)}^{2} - 4 \times \sqrt{5} \times ( - \sqrt{5} ) \\ = 1 - 4 \sqrt{5} \times ( - \sqrt{5} ) \\ = 1 + 4 \times 5 \\ = 1 + 20 \\ = 21$

Hope it helps you.