Question

Find the value of the discriminant of the equation x2+10x-7=0​

Answer 1

Answer: x 2 + 10x - 7 = 0

Step-by-step explanation:Comparing x 2 + 10x - 7 = 0 with ax 2 + bx + c = 0 a = 1, b = 10 , c = -7, b 2 - 4 ac = 10 2 - 4 x 1 x-7 = 100 + 28 = 128

Answer 2

Given:

An equation is given to us which is   $x^2+10x-7=0$.

To Find:

The value of discriminant of the equation ?

Step-by-step explanation:

• We have the equation of the form

                $x^2+10x-7=0$

• We will comapre the given equation with $ax^2+bx+c=0$

• On comapring we get a=1,b=10,c=-7

• We know discriminant of equation is given by

           [tex]D=b^2-4ac\\ put, a=1, b=10, c=-7\\\\ D=(10)^2-4\times1\times -7\\\\ D=100+28\\\\ D=128[/tex]

Thus discriminant is given by D=128.