Question

find the value of the discriminant of the quadratic equation 2x²-5x-1=0 and hence write the nature of its roots. ​

Answer 1

Answer:

33 ( real roots)

Step-by-step explanation:

2x²-5x-1=0

d= (-5)²-4(2)(-1)=0

d= 25+8=0

d= 33>0

so

real roots

Answer 2

Answer:

Concept:

finding the value of the discriminant of the given quadratic equation and writing the nature of its roots. ​

Step-by-step explanation:

Given:

quadratic equation 2x²-5x-1=0

Find:

Value of the discriminant, nature of its roots.

Solution:

Given equation is 2x²-5x-1=0

By comparing the above equation with $a x^{2}+b x+c=0$

a = 2, b = -5, c = -1

$\begin{aligned}&2 x^{2}-5 x-1=0 \\&d=(-5)^{2}-4(2)(-1)=0 \\&d=25+8=0 \\&d=33 > 0 \\\end{aligned}$

So Discriminant is 33 > 0. and having real roots.

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