Question

Find the value of the discriminant : y2 -3y-10=0

Answer 1

Answer:

49

Step-by-step explanation:

Comparing y²-3y-10=0 with ay²+by+c=0

we get,

a= 1

b= -3

c= -10

Discriminant = b²-4ac

= (-3)²-4×1×-10

=9+40

=49.

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Answer 2

To Find:

The value of the discriminant y²-3y-10=0

Solution:

Using ay²+by+c=0,

now comparing y²-3y-10=0 with ay²+by+c=0

a=1, b=-3, c=-10

The discriminant of a quadratic is the expression inside the radical of the quadratic formula.

Discriminant = b²-4ac

Now, substitute the value of a, b, c.

                     = b² -4ac

                     = (-3)²- 4(1)(-10)

Simplify each term

                     = 9 + 40

                     = 49

Hence, the value of the discriminant y²-3y-10=0 is 49.