Question

Find the value of the discriminat of each of the following equation
x²+x-1=0​

Answer 1

Answer:

${b}^{2} - 4ac = 1 - 4(1)( - 1) = 1 + 4 = 5$

Answer 2

Step-by-step explanation:

Given:-

$\\ \tt{:}\longrightarrow x^2+x-1=0$

To find:-

Discriminant value

Solution:-

Here

• a=1
• b=1
• c=-1

We know that

$\boxed{\sf Discriminant_{(D)}=b^2-4ac}$

$\\ \tt{:}\longrightarrow Discriminant_{(D)}=(1)^2-4(1)(-1)$

$\\ \tt{:}\longrightarrow Discriminant_{(D)}=1-4(-1)$

$\\ \tt{:}\longrightarrow Discriminant_{(D)}=1+4$

$\\ \tt{:}\longrightarrow Discriminant_{(D)}=5$

• As D>0 so this equation has real and unequal roots
• as D is not a perfect square so roots are not rational