Question

Find the value of the discriminate. 1. X2 - x-6=0. 2. x2-7x-30= 0​

Answer 1

Answer:

Given,

2x2+7x+52=0

or, 2x2+2x+5x+52=0

or, x2(x+2)+5(x+2)=0

or, (x2+5)(x+2)=0

⇒x=−25,−2.

Answer 2

Step-by-step explanation:

$x {}^{2} - x - 6 = 0 \\ or \: \: x {}^{2} - 3x + 2x - 6 = 0 \\ or \: \: x(x - 3) + 2(x - 3) = 0 \\ or \: \: (x - 3)(x + 2) = 0 \\ x - 3 = 0 \\ or \: \: x = 3 \\ x + 2 = 0 \\ or \: \: x = - 2$

$x {}^{2} - 7x - 30 = 0 \\ or \: \: x {}^{2} - 10x + 3x - 30 = 0 \\ or \: \: x(x - 10) + 3(x - 10) = 0 \\ or \: \: (x - 10)(x + 3) = 0 \\ \\ x - 10 = 0 \\ or \: \: x = 10 \\ x + 3 = 0 \\ or \: \: x = - 3$