Question

find the value of the equation c, if the equation x2-2(c+1)x + c 2 = 0 has real and equal roots​

Answer 1

c= -1/2

Step-by-step explanation:

x2 -2(ct1)x + c^2 =o

here, in this equation a = 1, b = -2(c *1),

C c^2

Since, the equation has real and equal

roots

D =0

b 2

- 4ac = O

-2(c+1)]2-4(1)(c^2) =0

4c+12 =

- 4c^2 0

4(c^2 + 2c+1) - 4c^2 0

4c 2+8c+4-4c 2 0

8c +40

4(2c +1) =0

2c+1 0

2c=1

c= -1/2.

Hope it helps you.