Question

find the value of the equation has two equal roots 2x2+kn+3=0​

Answer 1

Question:-

• Find the values of k for quadratic equation 2x² + kx + 3 = 0, so that they have two equal roots.

using formula:-

we know, quadratic equation will be equal only when

discriminant , D = b² - 4ac = 0

Solution:-

on comparing 2x² + kx + 3 = 0 with general form of quadratic equation , ax² + bx + c = 0 we get, a = 2, b = k and c = 3

so Discriminant , D

⟶ (k)² - 4(2)(3) = 0

⟶ k² - 24 = 0

⟶ k = ± √24

⟶ ± 2√6

hence, the value of k = 2√6 or -2√6

Answer 2

Answer:

so 4+kn+3=0

4+12kn-kn+3=0

4(1+3kn)-1(kn-3).

the formula to find root is

x=-b+-√b^2-4ac/2a