Question

find the value of the exppression x2 + 2x + 1 for x= -1​

Answer 1

$\tt\underline\purple{★Question:}$

Find the value of the exppression$\sf{ x² + 2x + 1 ~for~ x= -1}$

Given that,

$\rm{x=(-1)}$

Solution:

$\rm{x²+2x+1}$

Putting the value of x.

$\rm\leadsto{(-1)²+2×(-1)+1}$

$\rm\leadsto{(-1×-1)+2×(-1)+1}$

$\rm\leadsto{1+(-2)+1}$

$\rm\leadsto{1-2+1}$

$\leadsto\sf\cancel{-1+1}$

$\rm\leadsto{0}$

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Answer 2

Answer:

Given that,

[ tex]\rm{x=(-1)}x=(−1)[/tex]

Solution:

[ tex]\rm{x²+2x+1}x²+2x+1[/tex]

Putting the value of x.

[ tex]\rm\leadsto{(-1)²+2×(-1)+1}⇝(−1)²+2×(−1)+1[/tex]

[ tex]\rm\leadsto{(-1×-1)+2×(-1)+1}⇝(−1×−1)+2×(−1)+1[/tex]

[ tex]\rm\leadsto{1+(-2)+1}⇝1+(−2)+1[/tex]

[ tex]\rm\leadsto{1-2+1}⇝1−2+1[/tex]

[ tex]\leadsto\sf\cancel{-1+1}⇝ [/tex]

−1+1

[ tex]\rm\leadsto{0}⇝0[/tex]

Step-by-step explanation:

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