Find the value of the expression 16x² + 56xy + 49y2,
when x = 5 and y = 7.
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Answered by
0
Answer:
3430
Step-by-step explanation:
x^2=49 and xy=35
16 * 49 + 56*35 + 19*14 == 3430
Answered by
0
Answer:
(4x-7y)^2
Step-by-step explanation:
Rewrite
16 x^ 2 as ( 4 x ) ^2 .
( 4 x ) ^2 − 56 x y + 49 y ^2
Rewrite
49 y ^2 as ( 7 y ) ^2 .
( 4 x ) ^2 − 56 x y + ( 7 y ) ^2
Check the middle term by multiplying 2 a b and compare this result with the middle term in the original expression.
2 a b = 2 ⋅ ( 4 x ) ⋅ ( − 7 y )
Simplify.
2 a b = − 56 x y
Factor using the perfect square trinomial rule a ^2 − 2 a b + b ^2 = ( a − b ) ^2 , where a = 4 x and b = − 7 y .
( 4 x − 7 y ) ^2.
hope it helps........
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