Question

Find the value of the expression
3 (x³+y³+ z³-3xy) when x= -3
y = 2 and
z=1


Answer and I'll mark u brainliest ​

Answer 1

Answer:

0

Step-by-step explanation:

-3^3 = -27

2^3 = 8

1^3 = 1

3 x -3 x 2 = -18

3(-27 + 8 + 1 - (-18)) = 0

Answer 2

Step-by-step explanation:

= -3³ + 2³+ 1³

= -27 + 8+ 1

= -36

= 3xy =36

= 3x =36

= x = 36/3 = 12

now x = 3 and y = 12...

= 3x + 12y

=15.

=thus the answer is y = 12, and the answer is 15.

hope it helped