Find the value of the expression 3ab-5bc+6ca, when a=-2, b=-1, c=1.
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Answered by
0
Answer:
substitute the values of a,b and c in given equation
=(3×-2-1 ) - (5×-1×1) +(6×1×-2)
=6 -(-5) +(-12)
=6+5-12
=12-12
=0
the value of 3ab-5bc+6ca is 0
Answered by
2
Answer:
Answer:
substitute the values of a,b and c in given equation
=(3×-2-1 ) - (5×-1×1) +(6×1×-2)
=6 -(-5) +(-12)
=6+5-12
=12-12
=0
the value of 3ab-5bc+6ca is 0
Step-by-step explanation:
Hope this answer will help you.
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