Question

Find the value of the expression 4(a2+b2+2ab)-[4(a2+b2-2ab)-{-b3+4(a-3)}]
When a= 3 and b=1.​

Answer 1

Answer:

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Answer 2

Answer:

The value of expression is 49.

Explanation:

To calculate the value of :

$4(a^{2} + b^{2} +2ab) - [4(a^{2} +b^{2} -2ab)]-[-b^{3} + 4(a-3)]$

When $a = 3, b =1$

we get,

$= 4(3^{2} + 1^{2} +2*3*1)-[4(3^{2} - 1^{2} +2*3*1)]-[-1^{3} + 4(3-3)]$

upon simplification,

$= 4( 9+1+6)-[4(9+1-6)]-[-1+ 4*0]\\= 4(16)-4(4)+1\\= 64-16+1\\=49$

Therefore,The value of expression is $49.$

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