Find the value of the expression 64x^2+81y^2+144xy when x=11 and y= 4 3
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138
Substitute x = 11 and y = 4/3 into the expression.
64x² + 81y² + 144xy
= 64 (11)² + 81 (4/3)² + 144 (11) (4/3)
= 64 (121) + 81 (16/9) + 1584 (4/3)
= 7744 + 144 + 2112
= 10000
64x² + 81y² + 144xy
= 64 (11)² + 81 (4/3)² + 144 (11) (4/3)
= 64 (121) + 81 (16/9) + 1584 (4/3)
= 7744 + 144 + 2112
= 10000
Answered by
20
64x^2+81y^2+144xy
64(11)^2+81(4/3)^2+144(11) (4/3)
7744+144+2112
10000
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