Question

Find the value of the expression (9x^2 +24x +16), when x = 12 (using special identity)​

Answer 1

Answer:

1600

Step-by-step explanation:

$9 {x}^{2} + 24x + 16$

$= {(3x)}^{2} + 2(3x)(4) + {(4)}^{2}$

a² + 2ab + b² = (a + b)²

$= {(3x + 4)}^{2}$

x = 12

$= {(3 \times 12 \: \: + \: \: 4)}^{2}$

$= {(36 + 4)}^{2}$

$= {40}^{2}$

$= 1600$