Question

Find the value of the expression (cot(20-theta)+tan(70+theta)/sin(70+theta))sin(20-theta)

Answer 1

Answer:

cot (20+Ф) + tan (70+Ф) / sin(70+Ф)×sin(20-Ф)

=tan(90-20+Ф) + tan( 70+Ф) /sin (70+Ф)×cos(90-20+Ф)

= tan (70+Ф) + tan( 70+Ф)/sin (70+Ф)×cos(70+Ф)

=2tan (70+Ф)/sin (70+Ф)×cos(70+Ф)

=2×sin(70+Ф)/cos (70+Ф)÷sin (70+Ф)×cos(70+Ф)

=2×sin(70+Ф)/cos (70+Ф)× 1/sin (70+Ф)×cos(70+Ф)

              *sin(70+Ф) get cancelled

=2×1/cos (70+Ф)×cos (70+Ф)

=2×1/cos square (70+Ф)

=2sec square(70+Ф)....

Answer 2

this is the correct answer.
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