Question

find the value of the expression for X=1,Y=–2and Z=3:
(a)x³+y³+z=³–3xyz​

Answer 1

Step-by-step explanation:

GIVEN

x= 1 ,

y = -2 ,

z= 3

To Find -

x³+y³+z³–3xyz

Solution -

Put the value of x y and z in given polynomial

${x}^{3} + {y}^{3} + {z}^{3} - 3xyz \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ = {1}^{3} + {( - 2)}^{3} + {3}^{3} - 3(1) \times ( - 2) \times (3) \\ \\ = 1 - 8 + 27 + 18 \\ \\ = 38$

Required ans

Answer 2

Answer:

your answer is 38

Step-by-step explanation:

x=1

y=2

z=3