Question

Find the value of the expression for x = 2 y = 3, z = - 4 3x (x³ + y² + z³ - 3xyz)​

Answer 1

Question:-

Find the value of the expression for x = 2 y = 3, z = - 4 3x (x³ + y² + z³ - 3xyz)

Answer:-

3x(x³ + y² + z³ - 3xyz)

3x³ + 3xy² + 3xz³ - 9x²y

Now putting values, we get

3(2)³ + 3(2)(3)² + 3(2)(−4)³ − 9 × (2)² × (3) × (-4)

3 x 8 + 6 x 9 + 6 × (-64) - 9 × 4 × (-12)

24 + 54 + (-384) - 36 × (-12)

78 – 384 + 432

Adding the positive number first

432 + 78 - 384

510 – 384

126.

Answer 2

QUESTION:- Find the value of the expression for x = 2 y = 3, z = - 4 [ 3x (x³ + y² + z³ - 3xyz)]

Answe: First we will simplify the given equation

$\sf \: 3x (x³ + y² + z³ - 3xyz)$

$\sf \: 3x {}^{3} + 3xy {}^{2} + 3xz {}^{3} - 9x {}^{2} y$

Now putting values , we get

$\sf \: 3(2 {})^{3} + 3(2)(3) {}^{2} + 3(2)( - 4) {}^{3} - 9 \times (2 ){}^{2} \times (3) \times ( - 4)$

$\sf \: 3 \times 8 + 6 \times 9 + 6 \times ( - 64) - 9 \times 4 \times ( - 12)$

$\sf \: 24 + 54 + ( - 384) - 36 \times ( - 12)$

$\sf \: 78 - 384 + 432$

Adding the positive numbers first

$432 + 78 - 384$

$\sf \: 510 - 384$

$\sf126$

HOPE IT HELPS ✌