Question

Find the value of the expression when x=1, y = -1, z =0
a) 5y – y b) 3x² +2y + 3z² c) 2y² -3xyz

Answer 1

Answer:

a) -6

b) 1

c) 2

Step-by-step explanation:

a) 5(-1)-1= -6

b) 3(1)²+2(-1)+3(0)²= 3-2+0= 1

c) 2(-1)²-3(1)(-1)(0)= 2(1)-0= 2

Answer 2

Answer:

Given

x = 1, y = -1, z = 0

a)

$5y - y \\ = 5 \times ( - 1) - ( - 1) \\ = - 5 + 1 \\ = \: - 4$

b)

$3x {}^{2} + 2y + 3z {}^{2} \\ = 3 \times 1 {}^{2} + 2 \times ( - 1) \times 3 \times 0 \\ = 3 \times 1 + ( - 2) + 0 \\ = 3 - 2 \\ = 1$

c)

$2y {}^{2} - 3xyz \\ = 2 \times ( - 1) {}^{2} - 3 \times 1 \times ( - 1) \times 0 \\ = 2 \times 1 - 0 \\ = 2 \times 1 \\ = 2$

Hope, it will help you.