Question

Find the value of the expression when x=2 and y=3.
For 3x^y-y3
​

Answer 1

Answer:

-3

Step-by-step explanation:

3x^y-y3

3×2^3-3×3

3×8-9

3×-1

-3

hope this helps you!

pls mark me the brainliest

Answer 2

Answer:

Given- x=−2,y=3,z=1

So, x

3

+y

3

+z

3

−3xyz=(x+y+z)(x

2

+y

2

+z

2

−xy−yz−zx)

=(−2+3+1)((−2)

2

+(3)

2

+(1)

2

−(−6)−(−3)−(−2))

=(2)(4+9+1+6−3+2)

=(2)(19)

=38