find the value of the expression x(x-3)+7 when x =1
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Answered by
1
Answer:
5 is the answer may be it is correct
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Answered by
1
Step-by-step explanation:
x(x-3)^2+2
=x[x^2+9-6x]+2
=x^3+9x-6x^2+2
=x^2+2
=x^3-6x^2+9x+2
put x =1
=(1)^3-6(1)^2+9(1)+2
=1-6+11
=12-6
=6.
.
. .x(x-^3)+2=6.
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