Find the value of the expression (x+y)^2-7xy-8y^2 , when x =3 and y=4 .
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Here is your answer dear ☺️☺️☺️
=(3+4)^2-7(3)(4)-8(4)^2
= 7^2-7(12)-8(16)
= 49-84-128
= -163
Hope it help you dear ☺️☺️☺️
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