Question

Find the value of the expression (x+y)^2-7xy-8y^2 , when x = 3 and y = 4 .​

Answer 1

Answer:

Here is your answer dear ☺️☺️☺️

=(3+4)^2-7(3)(4)-8(4)^2

= 7^2-7(12)-8(16)

= 49 - 84 - 128

= -163

Hope it help you dear ☺️☺️☺️

Answer 2

Answer:

-163

Step-by-step explanation:

x = 3 ,y = 4

Now we subsitute the values with the expression

=(3+4)^2-7(3)(4)-8(4)^2  

= 7^2-7(12)-8(16)

= 49 - 84 - 128

= -163

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