Question

Find the value of the expression (x+y)^2-7xy-8y^2 , when x = 3 and y = 4.​

Answer 1

Answer:

Here is your answer dear ☺️☺️☺️

= (3+4)^2-7(3)(4)-8(4)^2

= 7^2-7(12)-8(16)

= 49-84-128

= -163

Hope it help you dear ☺️☺️☺️

Answer 2

(3+4)^2-7*3*4-8*4^2
7^2-21*4-8*16
49-84-128
-35-128
-163


I think its the correct answer