Find the value of the expression (x+y)^2-7xy-8y^2 , when x = 3 and y = 4.
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9
Answer:
Here is your answer dear ☺️☺️☺️
= (3+4)^2-7(3)(4)-8(4)^2
= 7^2-7(12)-8(16)
= 49-84-128
= -163
Hope it help you dear ☺️☺️☺️
Answered by
0
(3+4)^2-7*3*4-8*4^2
7^2-21*4-8*16
49-84-128
-35-128
-163
I think its the correct answer
7^2-21*4-8*16
49-84-128
-35-128
-163
I think its the correct answer
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