Question

find the value of the expression x2+4y-5 when x equals to 1​

Answer 1

Answer:

$\sf{ →{x}^{2} + 4y - 5} \\ \\ \sf{→{(1)}^{2} + 4y - 5} \\ \\ \sf{→1 + 4y - 5} \\ \\ \sf{→4y - 5 + 1} \\ \\{ \boxed{ \sf{→ 4y - 4}}}$

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