Question

find the value of the following ​

Answer 1

Answer:

sorry I don't have any answer...

Answer 2

Answer:

1) - 6q

2) q/r

Step-by-step explanation:

[NOTE: hey i have taking a,b,c instead of alpha,bita nd gama,as i have not those symbols on my keyboard]

x3+qx+r=0

Let the roots be a,b,c

Then,

a+b+c=0,

ab+bc+ca=q,

abc=−r

−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−

1) (a−b)^2+(b−c)^2+(c−a)^2

= 2(a^2+b^2+c^2)−2(ab+bc+ac)

=2{(a+b+c)^2−2(ab+bc+ac)}

−2(ab+bc+ac)

=2(a+b+c)^2−6(ab+bc+ac) = 0−6q = −6q

−−−−−−−−−−−−−−−−−−−

2) (b+c)^−1+(c+a)^−1+(a+b)^−1=∑1/(b+c)

As a+b+c=0

⇒∑1/(b+c) = −∑1/a = −(ab+bc+ac)/abc = -q/r = q/r