Question

find the value of the following (3 upon -1 + 2upon -1)+2 upon -2​

Answer 1

Answer:

Question:-

$\mathtt{ ( \frac{1}{3})^{ - 2} + (\frac{1}{4})^{ - 2} + ( \frac{1}{5} ) ^{2} }$

$\mathtt{( {3}^{ - 1} + 2^{ - 1} )+ {2}^{ - 2} }$

Formula used:-

$\mathtt{ {a}^{ - m} = \frac{1}{ {a}^{m} } }$

Solution:-

$\mathtt{ = ( \frac{1}{3})^{ - 2} + (\frac{1}{4})^{ - 2} + ( \frac{1}{5} ) ^{2} }$

$\mathtt{ = \frac{3}{ {1}^{2} } + \frac{4}{ {1}^{2}} + \frac{5}{ {1}^{2} } }$

$\mathtt{ = 3 + 4 + 5}$

$\fbox\purple{ = 12}$

$\mathtt{=( {3}^{ - 1} + 2^{ - 1} )+ {2}^{ - 2} }$

$\mathtt{ = (\frac{1}{3} + \frac{1}{2}) + \frac{1}{ {2}^{2} } }$

$\mathtt{ = \frac{2 + 3}{6} + \frac{1}{4} }$

$\mathtt{ = \frac{5}{6} + \frac{1}{4} }$

$\mathtt{ = \frac{10 + 3}{12} }$

$\mathtt{ = \frac{13}{12} }$

$\fbox\purple{13/12}$

Step-by-step explanation:

I hope this helps you mate