Math, asked by monica01475, 4 days ago

Find the value of the following:
(a)393x12+393x2 (b)47329x93+6x47329 answer pls

Answers

Answered by preeti353615
1

Answer:

  • 393 x 12 + 393 x 2  = 5502
  • 47329 x 93 + 6 x 47329 =4685571

Step-by-step explanation:

(a)393 x 12 + 393 x 2

Here 393 is common

= 393 (12 + 2)

= 393 (14)

=5502

So, 393 x 12 + 393 x 2  = 5502

(b)47329 x 93 + 6 x 47329

Here 47329 is common

= 47329 (93 + 6)

= 47329 (99)

= 4685571

So, 47329 x 93 + 6 x 47329 =4685571

Answered by pm9148805
1

Answer:

a) 393×12+393=5,109

b)47329×93+6×47329=4685571

Step-by-step explanation:

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