Question

Find the value of the following: a. 9x2+49y2+42xy, when x=3 and y=1​

Answer 1

$\implies\huge \mathfrak \red{question : }$

• Find the value of the following: 9x²+49y²+42xy , when x = 3 and y = 1

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$\implies \huge \mathfrak \blue{ \: answer : }$

$\huge\sf{ \boxed{ \underline{ \underline{ \purple{ \sf{256}}}}}}$

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$\implies \huge \mathfrak \pink{solution : }$

$\bf\underline{ Given}$

$\: \: \: \: \: \tt \huge \purple{9x²+49y²+42xy}$

$\: \: \: \: \: \tt \huge \purple{x = 3 \: and \: y = 1}$

• putting the values we get,

$\star \: \huge \sf{9(3) {}^{2} + 49(1) {}^{2} + 42(3)(1)}$

$\star \: \huge \sf{9(9) + 49(1) {}+ 42(3)}$

$\star \: \huge \sf81 + 49 + 126$

$\star \: \huge \sf256$

Answer 2

★GIVEN★

$\large{\sf{9x^2+49y^2+42xy}}$

• x = 3
• y = 1

★To Find★

The value.

★SOLUTION★

$\large{\sf{9x^2+49y^2+42xy}}$

Putting x = 3 and y = 1,

$\large\implies{\sf{9(3)^2+49(1)^2+42\times3\times1}}$

$\large\implies{\sf{(9\times9)+(49\times1)+126}}$

$\large\implies{\sf{81+49+126}}$

$\large\therefore\boxed{\bf{256}}$

The value of the equation is 256.