find the value of the following expression at a=1 and b=2 (1) a²+b²+3ab
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Answered by
4
Answer:
(1)²+(2)²+3×1×2
=1+4+6=11
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Answered by
0
Answer:
a²+b²+3ab
a= 1 , b = 2
substituting value of a and b in the given expression
=1²+ 2²+3×1×2
=1+4+6
=5+6
=11
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