Question

find the value of the following expression if a a=-1,b=0
(1) 3a2+2b2+a​

Answer 1

Step-by-step explanation:

Your answer:

$= 3( - 1 {)}^{2} + 2(0 {)}^{2} + ( - 1)$

[ squaring the numbers as directed ]

$= 3(1) + 2(0) - 1$

[ multiplying ]

$= 3 + 2 - 1$

[ mathematical functions ]

$= 5 - 1$

[ mathematics em functions ]

$= 4$

Answer 2

Answer:

Given,

a=-1,b=0

Substituting the values in the above expression,

=3×(-1)^2+2×0^2+-1

=3×1+2×0-1

=3+0-1

=3-1

=2

Hope it helps✌️