Question

Find the value of the following expressions for a = 4, b = 3.

(i) 3a + 2b (ii) 7a – 4b (iii) a2 + 2ab + b2 (iv) a3 – b3​

Answer 1

Answer:

a=4

b=3

(i) 3a+2b

=> 3(4)+2(3)

= 12+6 = 18.

(ii) 7a-4b

=> 7(4)-4(3)

= 28-12 = 16.

(iii) a^2+2ab+b^2

=> 4^2+2(4)(3)+3^2

= 16+24+9 = 49.

(iv) a^3-b^3

=> 4^3-3^3

= 64-27 = 37.