Question

Find the value of the following expressions for x = -2, y = -1, z = 3: 2x + 2y + 2z – xy – yz – zx​

Answer 1

Answer:

Given x = -2, y = -1, z = 3

Consider (x/y) + (y/z) + (z/x)

On substituting the given values we get, = (-2/-1) + (-1/3) + (3/-2)

The LCM of 3 and 2 is 6 = (12 – 2 – 9)/6 = (1/6)

Given x = -2, y = -1, z = 3

Consider x2 + y2 + z2 – xy – yz – zx

On substituting the given values we get, = (-2)2 + (-1)2 + 32 – (-2) (-1) – (-1) (3) – (3) (-2) = 4 + 1 + 9 – 2 + 3 + 6 = 23 – 2 = 21

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