Question

Find the value of the following expressions n cube+5n square+5n-2
when n-2

Answer 1

Find the value:

Step-by-step explanation:

$\ Given \ value:\\\\\ n^{3} +\ 5n^2\ +\ 5n-2 \\\\\ n-2 =0 \\\\\ find: \\\\\ n= ? \\\\\ Solution: \\\\\ n-2=0\\\\n=2\\\\\ put \ the \ value \ of \ n \ in \ given \ equation: \\\\\rightarrow \ n^{3} +\ 5n^2\ +\ 5n-2 \\\\\rightarrow \ (2)^{3} +\ 5(2)^2\ +\ 5(2)-2 \\\\\rightarrow \ (8) +\ 5(4)\ +\ 5(2)-2 \\\\\rightarrow \ 8 +\ 20 \ +\ 10 \ - 2 \\\\\rightarrow \ 8 +\ 20 \ +\ 8 \\\\\rightarrow \ 16 +\ 20 \\\\\rightarrow \ 36$

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Answer 2

Answer:

5(-2)-2=-10-2=-12

5(-2)^2+5(-2)-2=5(4)-10-2=20-12=8

(-2)^3+5(-2)^2+5(-2)-2=-8+5(4)-10-2=-8+20-12=-12-12=-24

Step-by-step explanation: