Question

find the value of the following expressions when x=(-2) (1)3x³-4x²-5x+8​

Answer 1

Answer:

x = -2

3x³-4x²-5x+8

3(-2)³ - 4(-2)² - 5(-2) + 8

3(-8) - 4(4) + 10 +8

-24 - 16 + 18

-24 + 2

- 22

Answer 2

Step-by-step explanation:

p(-1)= -3–2+1 +4 = 0. -1 is a root p(x). Thus p(x) = (x + 1)(3x^2 -5x + 4). Regarding the other 2 roots, since the discriminant of the quadratic is (25 -48) = -23 is negative the two roots are complex. They are: (-5 +/- i sqrt(23))/3