find the value of the following linear equations X by 2-5=x by 3-4
Answers
Answered by
0
Answer:
undue shih isuzu 3ue7 co
Answered by
3
Answer:
(3k+1)x+3y−2=0
(k2+1)x+(k−2)y−5=0
Answer
The given system of equations is
(3k+1)x+3y−2=0
(k2+1)x+(k−2)y−5=0
This is of the form a1x+b1y+c1=0
a2x+b2y+c2=0,
where, a1=3k+1,b1=3,c1=−2
and a1=k2+1,b2=k−2,c2=−5
For no solution, we must have
a2a1=b2b
Similar questions