Question

find the value of the following sin 60 cos 30​

Answer 1

Answer:

In aright triangle ABC base angle ,30° ,apex angle=90°–30° =60° let base is 1 , perpendicular is x, Therefore sin30°= x/hypotenuse=1/2 ,or hypotenuse=2x,cos 30 =1/2x,x^2+1=4x^2 or x=1/√3 Therefore

cos 30°=√3/2,sin60°=cos30°( by orientation base at perpendicular) therefore sin60°+cos30°=2×√3/2=√3 (answer)

Answer 2

Answer:

$\frac{3}{4}$

Step-by-step explanation:

Assuming the question is $\sin{60}*\cos{30}$.

$\sin{60}=\frac{\sqrt{3}}{2}$

$\cos{30}=\frac{\sqrt{3}}{2}$

$\sin{60}*\cos{30} = \frac{\sqrt{3}}{2}* \frac{\sqrt{3}}{2}=\frac{3}{4}$