Question

find the value of the following: x³+y³+3xy when x+y=1

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Answer 1

Answer:

Given,

x³+y³+3xy

=> (x+y)(x²+y²-xy)+3xy

=> (1).(x²+y²-xy)+3xy

=> (x²+y²-xy)+3xy

=> x²+y²+2xy

=> (x+y)²

=> (1)²=1 Ans.