find the value of the following x³+y³if x+y =3 and xy = 2
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Answered by
0
Answer:
we know that x^3+y^3=(x+y)^3-3xy(x+y)
puting x+y=3 and xy =2 we get,
= (3)^3-3×2(3)
=27-3×6
=27-18
=9
Step-by-step explanation:
Answered by
1
Step-by-step explanation:
x^3+y^3
We know that, (x+y)^3=x^3+y^3+3xy(x+y)
substitute values
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