Question

Find the value of the followingwithout using trignometric tables cos50°/2sin40°+4(cosec square 59°-tan square31°)/3tan square 45°-2/3 tan 12° tan 78°sin90°

Answer 1

Given 4(sec2 59°-cot231)/3-2/3 Sin 90°+tan256xtan234 = (x/3) (x/3) = 4[sec2 (90° – 31°) - cot231)/3] - 2/3 (1) + tan2(90° – 34°) x tan234 (x/3) = 4[cosec2 31° - cot231°)/3] - 2/3 + cot2 34° x tan234 (x/3) = 4[1]/3 - 2/3 + 1 (x/3) = 4/3 - 2/3 + 1 (x/3) = 2/3 + 1 = 5/3 Hence x = 5