Question

Find the value of the given expressions when a=0, b=-1, c=1 i) a3 – b3 ii) a2 + 2ab +b3 iii) 3ab + 3ac + c2

Answer 1

Answer:a) 3 b) -3 c) 2

Step-by-step explanation:

Answer 2

Answer:

Hope it helps :)

Step-by-step explanation:

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$(i)~a^3-b^3\\\\\\= (0)^3-(-1)^3\\\\\\= 0-(-1)\\\\\\=0+1\\\\\\=1\\\\\\\\(ii)~a^2+2ab+b^3\\\\\\=(0)^2+(2*0*-1)+(-1)^3\\\\\\=0+0+(-1)\\\\\\=0-1\\\\\\=-1\\\\\\\\(iii)~3ab+3ac+c^2\\\\\\=(3*0*-1)+(3*0*1)+(1)^2\\\\\\=0+0+1\\\\\\=1$

NOTE : Any Number Multiplied with 0 = 0