find the value of the k for whichthe following pair of the equation which has no solution x+2y=3,(k-1)x +(k+1)y=)(k+2)
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We know that the condition of no solution that is a1/a2=b1/b2 but not equal to c1/c2
So, 1/(k-1)=2/(k+2)
k+2=2k-2
k-2k=-2-2
-k=-4
K=4
I hope it will help you
please mark as brainliest answer
So, 1/(k-1)=2/(k+2)
k+2=2k-2
k-2k=-2-2
-k=-4
K=4
I hope it will help you
please mark as brainliest answer
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