Question

find the value of the k if roots are real. 3x^2-5x+k=0​

Answer 1

Answer:

The given quadric equation is 3x2 - 5x + 2k = 0, and roots are real and equal

Then find the value of k.

Here, a = 3, b = -5 and c = 2k

As we know that D = b2 - 4ac

Putting the value of a = 3, b = -5 and c = 2k

= (-5)2 - 4 x (3) x (2k)

= 25 - 24k

The given equation will have real and equal roots, if D = 0

Thus,

25 - 24k = 0

24k = 25

k = 25/24

Therefore, the value of k = 25/24.

Answer 2

Answer:

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