Find the value of the middle term of the A.P -6,-2,2,-.....,58. *
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here, a = -11,d= -7-(-11) = 4,an = 49
we have an = a + (n-1) d
so ,49=-11 +(n-1) ×4
i.e., 60=(n-1) ×4
i.e., n=16
as n is an even number , there will be two middle terms witch are
(16/2)th and (16/2+1)th
i.e., the 8th term and 9th trem
a8 = a + 7d = - 11 + 7 × 4 = 17
a9 = a + 8d = - 11 + 8 × 4 = 21
so, the value of the two middle most trem of 17 and 21 , respectively...
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